Cleanest way to write retry logic?

Question

Occasionally I have a need to retry an operation several times before giving up. My code is like:

int retries = 3;
while(true) {
  try {
    DoSomething();
         


        

Answer 1

I had the need to pass some parameter to my method to retry, and have a result value; so i need an expression.. I build up this class that does the work (it is inspired to the the LBushkin's one) you can use it like this:

static void Main(string[] args)
{
    // one shot
    var res = Retry.Do(() => retryThis("try"), 4, TimeSpan.FromSeconds(2), fix);

    // delayed execute
    var retry = new Retry(() => retryThis("try"), 4, TimeSpan.FromSeconds(2), fix);
    var res2 = retry.Execute();
}

static void fix()
{
    Console.WriteLine("oh, no! Fix and retry!!!");
}

static string retryThis(string tryThis)
{
    Console.WriteLine("Let's try!!!");
    throw new Exception(tryThis);
}

public class Retry
{
    Expression> _Method;
    int _NumRetries;
    TimeSpan _RetryTimeout;
    Action _OnFailureAction;

    public Retry(Expression> method, int numRetries, TimeSpan retryTimeout, Action onFailureAction)
    {
        _Method = method;
        _NumRetries = numRetries;
        _OnFailureAction = onFailureAction;
        _RetryTimeout = retryTimeout;
    }

    public TResult Execute()
    {
        TResult result = default(TResult);
        while (_NumRetries > 0)
        {
            try
            {
                result = _Method.Compile()();
                break;
            }
            catch
            {
                _OnFailureAction();
                _NumRetries--;
                if (_NumRetries <= 0) throw; // improved to avoid silent failure
                Thread.Sleep(_RetryTimeout);
            }
        }
        return result;
    }

    public static TResult Do(Expression> method, int numRetries, TimeSpan retryTimeout, Action onFailureAction)
    {
        var retry = new Retry(method, numRetries, retryTimeout, onFailureAction);
        return retry.Execute();
    }
}

ps. the LBushkin's solution does one more retry =D