Javascript call() & apply() vs bind()?

Question

I already know that apply and call are similar functions which setthis (context of a function).

The difference is with the way

Answer 1

Syntax

• call(thisArg, arg1, arg2, ...)
• apply(thisArg, argsArray)
• bind(thisArg[, arg1[, arg2[, ...]]])

Here

• thisArg is the object
• argArray is an array object
• arg1, arg2, arg3,... are additional arguments

function printBye(message1, message2){
    console.log(message1 + " " + this.name + " "+ message2);
}

var par01 = { name:"John" };
var msgArray = ["Bye", "Never come again..."];

printBye.call(par01, "Bye", "Never come again...");
//Bye John Never come again...

printBye.call(par01, msgArray);
//Bye,Never come again... John undefined

//so call() doesn't work with array and better with comma seperated parameters 

//printBye.apply(par01, "Bye", "Never come again...");//Error

printBye.apply(par01, msgArray);
//Bye John Never come again...

var func1 = printBye.bind(par01, "Bye", "Never come again...");
func1();//Bye John Never come again...

var func2 = printBye.bind(par01, msgArray);
func2();//Bye,Never come again... John undefined
//so bind() doesn't work with array and better with comma seperated parameters