round() for float in C++

Question

I need a simple floating point rounding function, thus:

double round(double);

round(0.1) = 0
round(-0.1) = 0
round(-0.9) = -1

I can find

Answer 1

Based on Kalaxy's response, the following is a templated solution that rounds any floating point number to the nearest integer type based on natural rounding. It also throws an error in debug mode if the value is out of range of the integer type, thereby serving roughly as a viable library function.

    // round a floating point number to the nearest integer
    template 
    int Round(Arg arg)
    {
#ifndef NDEBUG
        // check that the argument can be rounded given the return type:
        if (
            (Arg)std::numeric_limits::max() < arg + (Arg) 0.5) ||
            (Arg)std::numeric_limits::lowest() > arg - (Arg) 0.5)
            )
        {
            throw std::overflow_error("out of bounds");
        }
#endif

        return (arg > (Arg) 0.0) ? (int)(r + (Arg) 0.5) : (int)(r - (Arg) 0.5);
    }