round() for float in C++

Question

I need a simple floating point rounding function, thus:

double round(double);

round(0.1) = 0
round(-0.1) = 0
round(-0.9) = -1

I can find

Answer 1

There are 2 problems we are looking at:

1. rounding conversions
2. type conversion.

Rounding conversions mean rounding ± float/double to nearest floor/ceil float/double. May be your problem ends here. But if you are expected to return Int/Long, you need to perform type conversion, and thus "Overflow" problem might hit your solution. SO, do a check for error in your function

long round(double x) {
   assert(x >= LONG_MIN-0.5);
   assert(x <= LONG_MAX+0.5);
   if (x >= 0)
      return (long) (x+0.5);
   return (long) (x-0.5);
}

#define round(x) ((x) < LONG_MIN-0.5 || (x) > LONG_MAX+0.5 ?\
      error() : ((x)>=0?(long)((x)+0.5):(long)((x)-0.5))

from : http://www.cs.tut.fi/~jkorpela/round.html