What\'s a quick-and-dirty way to make sure that only one instance of a shell script is running at a given time?
This example is explained in the man flock, but it needs some impovements, because we should manage bugs and exit codes:
#!/bin/bash
#set -e this is useful only for very stupid scripts because script fails when anything command exits with status more than 0 !! without possibility for capture exit codes. not all commands exits >0 are failed.
( #start subprocess
# Wait for lock on /var/lock/.myscript.exclusivelock (fd 200) for 10 seconds
flock -x -w 10 200
if [ "$?" != "0" ]; then echo Cannot lock!; exit 1; fi
echo $$>>/var/lock/.myscript.exclusivelock #for backward lockdir compatibility, notice this command is executed AFTER command bottom ) 200>/var/lock/.myscript.exclusivelock.
# Do stuff
# you can properly manage exit codes with multiple command and process algorithm.
# I suggest throw this all to external procedure than can properly handle exit X commands
) 200>/var/lock/.myscript.exclusivelock #exit subprocess
FLOCKEXIT=$? #save exitcode status
#do some finish commands
exit $FLOCKEXIT #return properly exitcode, may be usefull inside external scripts
You can use another method, list processes that I used in the past. But this is more complicated that method above. You should list processes by ps, filter by its name, additional filter grep -v grep for remove parasite nad finally count it by grep -c . and compare with number. Its complicated and uncertain