iOS 6 apps - how to deal with iPhone 5 screen size? [duplicate]

Answer 1

@interface UIDevice (Screen)
typedef enum
{
    iPhone          = 1 << 1,
    iPhoneRetina    = 1 << 2,
    iPhone5         = 1 << 3,
    iPad            = 1 << 4,
    iPadRetina      = 1 << 5

} DeviceType;

+ (DeviceType)deviceType;
@end

.m

#import "UIDevice+Screen.h"
@implementation UIDevice (Screen)

+ (DeviceType)deviceType
{
    DeviceType thisDevice = 0;
    if ([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone)
    {
        thisDevice |= iPhone;
        if ([[UIScreen mainScreen] respondsToSelector: @selector(scale)])
        {
            thisDevice |= iPhoneRetina;
            if ([[UIScreen mainScreen] bounds].size.height == 568)
                thisDevice |= iPhone5;
        }
    }
    else
    {
        thisDevice |= iPad;
        if ([[UIScreen mainScreen] respondsToSelector: @selector(scale)])
            thisDevice |= iPadRetina;
    }
    return thisDevice;
}

@end

This way, if you want to detect whether it is just an iPhone or iPad (regardless of screen-size), you just use:

if ([UIDevice deviceType] & iPhone) 

or

if ([UIDevice deviceType] & iPad)

If you want to detect just the iPhone 5, you can use

if ([UIDevice deviceType] & iPhone5)

As opposed to Malcoms answer where you would need to check just to figure out if it's an iPhone,

if ([UIDevice currentResolution] == UIDevice_iPhoneHiRes || 
    [UIDevice currentResolution] == UIDevice_iPhoneStandardRes || 
    [UIDevice currentResolution] == UIDevice_iPhoneTallerHiRes)`

Neither way has a major advantage over one another, it is just a personal preference.