How to iterate over arguments in a Bash script

Question

I have a complex command that I\'d like to make a shell/bash script of. I can write it in terms of $1 easily:

foo $1 args -o $1.ext
         


        

Answer 1

aparse() {
while [[ $# > 0 ]] ; do
  case "$1" in
    --arg1)
      varg1=${2}
      shift
      ;;
    --arg2)
      varg2=true
      ;;
  esac
  shift
done
}

aparse "$@"