How can I pass arguments to a batch file?

Question

I need to pass an ID and a password to a batch file at the time of running rather than hardcoding them into the file.

Here\'s what the command line looks like:

Answer 1

For to use looping get all arguments and in pure batch:

Obs: For using without: ?*&<>

---

@echo off && setlocal EnableDelayedExpansion

 for %%Z in (%*)do set "_arg_=%%Z" && set/a "_cnt+=1+0" && (
     call set "_arg_[!_cnt!]=!_arg_!" && for /l %%l in (!_cnt! 1 !_cnt!
     )do echo/ The argument n:%%l is: !_arg_[%%l]!
 )

goto :eof 

Your code is ready to do something with the argument number where it needs, like...

 @echo off && setlocal EnableDelayedExpansion

 for %%Z in (%*)do set "_arg_=%%Z" && set/a "_cnt+=1+0" && call set "_arg_[!_cnt!]=!_arg_!"
 
 fake-command /u !_arg_[1]! /p !_arg_[2]! > test-log.txt