Rendering JSON objects using a Django template after an Ajax call

Question

I\'ve been trying to understand what\'s the optimal way to do Ajax in Django. By reading stuff here and there I gathered that the common process is:

1. formul

Answer 1

Hey thanks vikingosegundo!

I like using decorators too :-). But in the meanwhile I've been following the approach suggested by the snippet I was mentioning above. Only thing, use instead the snippet n. 942 cause it's an improved version of the original one. Here's how it works:

Imagine you have a template (e.g., 'subtemplate.html') of whatever size that contains a useful block you can reuse:

     ........
    
          
        {% block results %}
            {% for el in items %}
                   
{{el|capfirst}}
            {% endfor %}
        {% endblock %}      
    


     ........

By importing in your view file the snippet above you can easily reference to any block in your templates. A cool feature is that the inheritance relations among templates are taken into consideration, so if you reference to a block that includes another block and so on, everything should work just fine. So, the ajax-view looks like this:

from django.template import loader
# downloaded from djangosnippets.com[942]
from my_project.snippets.template import render_block_to_string

def ajax_view(request):
    # some random context
    context = Context({'items': range(100)})
    # passing the template_name + block_name + context
    return_str = render_block_to_string('standard/subtemplate.html', 'results', context)
    return HttpResponse(return_str)