Fortran: integer*4 vs integer(4) vs integer(kind=4)

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南笙 2020-11-22 02:32

I\'m trying to learn Fortran and I\'m seeing a lot of different definitions being passed around and I\'m wondering if they\'re trying to accomplish the same thing. What is t

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  •  有刺的猬
    2020-11-22 03:02

    In Fortran >=90, the best approach is use intrinsic functions to specify the precision you need -- this guarantees both portability and that you get the precision that you need. For example, to obtain integers i and my_int that will support at least 8 decimal digits, you could use:

    integer, parameter :: RegInt_K = selected_int_kind (8)
    integer (kind=RegInt_K) :: i, my_int
    

    Having defined RegInt_K (or whatever name you select) as a parameter, you can use it throughout your code as a symbol. This also makes it easy to change the precision.

    Requesting 8 or 9 decimal digits will typically obtain a 4-byte integer.

    integer*4 is an common extension going back to old FORTRAN to specify a 4-byte integer. Although, this syntax isn't and was never standard Fortran.

    integer (4) or integer (RegInt_K) are short for integer (kind=4) or integer (kind=RegInt_K). integer (4) is not the same as integer*4 and is non-portable -- the language standard does not specify the numeric values of kinds. Most compilers use the kind=4 for 4-byte integers -- for these compilers integer*4 and integer(4) will provide the same integer type -- but there are exceptions, so integer(4) is non-portable and best avoided.

    The approach for reals is similar.

    UPDATE: if you don't want to specify numeric types by the required precision, but instead by the storage that they will use, Fortran 2008 provides a method. reals and integers can be specified by the number of bits of storage after useing the ISO_FORTRAN_ENV module, for example, for a 4-byte (32-bit) integer:

    use ISO_FORTRAN_ENV
    integer (int32) :: MyInt
    

    The gfortran manual has documentation under "intrinsic modules".

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