How to compare two floating point numbers in Bash?

Question

I am trying hard to compare two floating point numbers within a bash script. I have to variables, e.g.

let num1=3.17648e-22
let num2=1.5

No

Answer 1

Using bashj (https://sourceforge.net/projects/bashj/ ), a bash mutant with java support, you just write (and it IS easy to read):

#!/usr/bin/bashj

#!java
static int doubleCompare(double a,double b) {return((a>b) ? 1 : (a $num2" ; fi
if [ $comp == -1 ] ; then echo "$num2 > $num1" ; fi

Of course bashj bash/java hybridation offers much more...