Simple regular expression for a decimal with a precision of 2

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闹比i
闹比i 2020-11-22 02:02

What is the regular expression for a decimal with a precision of 2?

Valid examples:

123.12
2
56754
92929292929292.12
0.21
3.1
17条回答
  •  無奈伤痛
    2020-11-22 02:52

    Valid regex tokens vary by implementation. A generic form is:

    [0-9]+(\.[0-9][0-9]?)?
    

    More compact:

    \d+(\.\d{1,2})?
    

    Both assume that both have at least one digit before and one after the decimal place.

    To require that the whole string is a number of this form, wrap the expression in start and end tags such as (in Perl's form):

    ^\d+(\.\d{1,2})?$
    

    To match numbers without a leading digit before the decimal (.12) and whole numbers having a trailing period (12.) while excluding input of a single period (.), try the following:

    ^(\d+(\.\d{0,2})?|\.?\d{1,2})$
    

    Added

    Wrapped the fractional portion in ()? to make it optional. Be aware that this excludes forms such as 12. Including that would be more like ^\d+\\.?\d{0,2}$.

    Added

    Use ^\d{1,6}(\.\d{1,2})?$ to stop repetition and give a restriction to whole part of the decimal value.

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