Swift how to sort array of custom objects by property value

Question

lets say we have a custom class named imageFile and this class contains two properties.

class imageFile  {
    var fileName = String()
    var fileID = Int(         


        

Answer 1

Swift 4.0, 4.1 & 4.2 First, I created mutable array of type imageFile() as shown below

var arr = [imageFile]()

Create mutable object image of type imageFile() and assign value to properties as shown below

   var image = imageFile()
   image.fileId = 14
   image.fileName = "A"

Now, append this object to array arr

    arr.append(image)

Now, assign the different properties to same mutable object i.e image

   image = imageFile()
   image.fileId = 13
   image.fileName = "B"

Now, again append image object to array arr

    arr.append(image)

Now, we will apply Ascending order on fileId property in array arr objects. Use < symbol for Ascending order

 arr = arr.sorted(by: {$0.fileId < $1.fileId}) // arr has all objects in Ascending order
 print("sorted array is",arr[0].fileId)// sorted array is 13
 print("sorted array is",arr[1].fileId)//sorted array is 14

Now, we will apply Descending order on on fileId property in array arr objects. Use > symbol for Descending order

 arr = arr.sorted(by: {$0.fileId > $1.fileId}) // arr has all objects in Descending order
 print("Unsorted array is",arr[0].fileId)// Unsorted array is 14
 print("Unsorted array is",arr[1].fileId)// Unsorted array is 13

In Swift 4.1. & 4.2 For sorted order use

let sortedArr = arr.sorted { (id1, id2) -> Bool in
  return id1.fileId < id2.fileId // Use > for Descending order
}