RegEx: Grabbing values between quotation marks

Question

I have a value like this:

\"Foo Bar\" \"Another Value\" something else

What regex will return the

Answer 1

Unlike Adam's answer, I have a simple but worked one:

(["'])(?:\\\1|.)*?\1

And just add parenthesis if you want to get content in quotes like this:

(["'])((?:\\\1|.)*?)\1

Then $1 matches quote char and $2 matches content string.