RegEx: Grabbing values between quotation marks

Question

I have a value like this:

\"Foo Bar\" \"Another Value\" something else

What regex will return the

Answer 1

The pattern (["'])(?:(?=(\\?))\2.)*?\1 above does the job but I am concerned of its performances (it's not bad but could be better). Mine below it's ~20% faster.

The pattern "(.*?)" is just incomplete. My advice for everyone reading this is just DON'T USE IT!!!

For instance it cannot capture many strings (if needed I can provide an exhaustive test-case) like the one below:

$string = 'How are you? I\'m fine, thank you';

The rest of them are just as "good" as the one above.

If you really care both about performance and precision then start with the one below:

/(['"])((\\\1|.)*?)\1/gm

In my tests it covered every string I met but if you find something that doesn't work I would gladly update it for you.

Check my pattern in an online regex tester.