I have two points in 3D:
(xa, ya, za) (xb, yb, zb)
And I want to calculate the distance:
dist = sqrt((xa-xb)^2 + (ya-yb)^2 + (
Use numpy.linalg.norm:
dist = numpy.linalg.norm(a-b)
You can find the theory behind this in Introduction to Data Mining
This works because the Euclidean distance is the l2 norm, and the default value of the ord parameter in numpy.linalg.norm is 2.
numpy.linalg.norm