What does sizeof(&array) return?

Question

Following the question: How come an array's address is equal to its value in C?

#include 
#define N 10    
char str2[N]={\"Hello\"};
int m         


        

Answer 1

str2 is of type char [10] (i.e, array 10 ofchar`)

&str2 is of type char (*)[10] (i.e., pointer to an array 10 of char).

So sizeof (&str2) yields the size of an objet of pointer type char (*)[10]