I have a string in Bash:
string=\"My string\"
How can I test if it contains another string?
if [ $string ?? \'foo\' ]; then
So there are lots of useful solutions to the question - but which is fastest / uses the fewest resources?
Repeated tests using this frame:
/usr/bin/time bash -c 'a=two;b=onetwothree; x=100000; while [ $x -gt 0 ]; do TEST ; x=$(($x-1)); done'
Replacing TEST each time:
[[ $b =~ $a ]] 2.92 user 0.06 system 0:02.99 elapsed 99% CPU
[ "${b/$a//}" = "$b" ] 3.16 user 0.07 system 0:03.25 elapsed 99% CPU
[[ $b == *$a* ]] 1.85 user 0.04 system 0:01.90 elapsed 99% CPU
case $b in *$a):;;esac 1.80 user 0.02 system 0:01.83 elapsed 99% CPU
doContain $a $b 4.27 user 0.11 system 0:04.41 elapsed 99%CPU
(doContain was in F. Houri's answer)
And for giggles:
echo $b|grep -q $a 12.68 user 30.86 system 3:42.40 elapsed 19% CPU !ouch!
So the simple substitution option predictably wins whether in an extended test or a case. The case is portable.
Piping out to 100000 greps is predictably painful! The old rule about using external utilities without need holds true.