How to find overlapping matches with a regexp?

Question

>>> match = re.findall(r\'\\w\\w\', \'hello\')
>>> print match
[\'he\', \'ll\']

Since \\w\\w means two characters, \'he\' and \'l

Answer 1

Am no regex expert but I would like to answer my similar question.

If you want to use a capture group with the lookahead:

example regex: (\d)(?=.\1)

string: 5252

this will match the first 5 as well as the first 2

The (\d) is to make a capture group, (?=\d\1) is to match any digit followed by the capture group 1 without consuming the string, thus allow overlapping