Initialization of an ArrayList in one line

后端 未结 30 2063
北恋
北恋 2020-11-22 01:10

I wanted to create a list of options for testing purposes. At first, I did this:

ArrayList places = new ArrayList();
places.add(\         


        
30条回答
  •  南笙
    南笙 (楼主)
    2020-11-22 01:46

    Simply use below code as follows.

    List list = new ArrayList() {{
                add("A");
                add("B");
                add("C");
    }};
    

提交回复
热议问题