Initialization of an ArrayList in one line

后端 未结 30 2227
北恋
北恋 2020-11-22 01:10

I wanted to create a list of options for testing purposes. At first, I did this:

ArrayList places = new ArrayList();
places.add(\         


        
30条回答
  •  悲哀的现实
    2020-11-22 01:42

    Actually, probably the "best" way to initialize the ArrayList is the method you wrote, as it does not need to create a new List in any way:

    ArrayList list = new ArrayList();
    list.add("A");
    list.add("B");
    list.add("C");
    

    The catch is that there is quite a bit of typing required to refer to that list instance.

    There are alternatives, such as making an anonymous inner class with an instance initializer (also known as an "double brace initialization"):

    ArrayList list = new ArrayList() {{
        add("A");
        add("B");
        add("C");
    }};
    

    However, I'm not too fond of that method because what you end up with is a subclass of ArrayList which has an instance initializer, and that class is created just to create one object -- that just seems like a little bit overkill to me.

    What would have been nice was if the Collection Literals proposal for Project Coin was accepted (it was slated to be introduced in Java 7, but it's not likely to be part of Java 8 either.):

    List list = ["A", "B", "C"];
    

    Unfortunately it won't help you here, as it will initialize an immutable List rather than an ArrayList, and furthermore, it's not available yet, if it ever will be.

提交回复
热议问题