I\'d like to identify groups of continuous numbers in a list, so that:
myfunc([2, 3, 4, 5, 12, 13, 14, 15, 16, 17, 20])
Returns:
The "naive" solution which I find somewhat readable atleast.
x = [2, 3, 4, 5, 12, 13, 14, 15, 16, 17, 22, 25, 26, 28, 51, 52, 57]
def group(L):
first = last = L[0]
for n in L[1:]:
if n - 1 == last: # Part of the group, bump the end
last = n
else: # Not part of the group, yield current group and start a new
yield first, last
first = last = n
yield first, last # Yield the last group
>>>print list(group(x))
[(2, 5), (12, 17), (22, 22), (25, 26), (28, 28), (51, 52), (57, 57)]