Is it possible to search every field of every table for a particular value in Oracle?
There are hundreds of tables with thousands of rows in some tables so I know th
I know this is an old topic. But I see a comment to the question asking if it could be done in SQL
rather than using PL/SQL
. So thought to post a solution.
The below demonstration is to Search for a VALUE in all COLUMNS of all TABLES in an entire SCHEMA:
Let's look for the value KING
in SCOTT
schema.
SQL> variable val varchar2(10)
SQL> exec :val := 'KING'
PL/SQL procedure successfully completed.
SQL> SELECT DISTINCT SUBSTR (:val, 1, 11) "Searchword",
2 SUBSTR (table_name, 1, 14) "Table",
3 SUBSTR (column_name, 1, 14) "Column"
4 FROM cols,
5 TABLE (xmlsequence (dbms_xmlgen.getxmltype ('select '
6 || column_name
7 || ' from '
8 || table_name
9 || ' where upper('
10 || column_name
11 || ') like upper(''%'
12 || :val
13 || '%'')' ).extract ('ROWSET/ROW/*') ) ) t
14 ORDER BY "Table"
15 /
Searchword Table Column
----------- -------------- --------------
KING EMP ENAME
SQL>
Let's look for the value 20
in SCOTT
schema.
SQL> variable val NUMBER
SQL> exec :val := 20
PL/SQL procedure successfully completed.
SQL> SELECT DISTINCT SUBSTR (:val, 1, 11) "Searchword",
2 SUBSTR (table_name, 1, 14) "Table",
3 SUBSTR (column_name, 1, 14) "Column"
4 FROM cols,
5 TABLE (xmlsequence (dbms_xmlgen.getxmltype ('select '
6 || column_name
7 || ' from '
8 || table_name
9 || ' where upper('
10 || column_name
11 || ') like upper(''%'
12 || :val
13 || '%'')' ).extract ('ROWSET/ROW/*') ) ) t
14 ORDER BY "Table"
15 /
Searchword Table Column
----------- -------------- --------------
20 DEPT DEPTNO
20 EMP DEPTNO
20 EMP HIREDATE
20 SALGRADE HISAL
20 SALGRADE LOSAL
SQL>