MongoDb query condition on comparing 2 fields

Question

I have a collection T, with 2 fields: Grade1 and Grade2, and I want to select those with condition Grade1 > Grade2, ho

Answer 1

If your query consists only of the $where operator, you can pass in just the JavaScript expression:

db.T.find("this.Grade1 > this.Grade2");

---

For greater performance, run an aggregate operation that has a $redact pipeline to filter the documents which satisfy the given condition.

The $redact pipeline incorporates the functionality of $project and $match to implement field level redaction where it will return all documents matching the condition using $$KEEP and removes from the pipeline results those that don't match using the $$PRUNE variable.

---

Running the following aggregate operation filter the documents more efficiently than using $where for large collections as this uses a single pipeline and native MongoDB operators, rather than JavaScript evaluations with $where, which can slow down the query:

db.T.aggregate([
    {
        "$redact": {
            "$cond": [
                { "$gt": [ "$Grade1", "$Grade2" ] },
                "$$KEEP",
                "$$PRUNE"
            ]
        }
    }
])

which is a more simplified version of incorporating the two pipelines $project and $match:

db.T.aggregate([
    {
        "$project": {
            "isGrade1Greater": { "$cmp": [ "$Grade1", "$Grade2" ] },
            "Grade1": 1,
            "Grade2": 1,
            "OtherFields": 1,
            ...
        }
    },
    { "$match": { "isGrade1Greater": 1 } }
])

With MongoDB 3.4 and newer:

db.T.aggregate([
    {
        "$addFields": {
            "isGrade1Greater": { "$cmp": [ "$Grade1", "$Grade2" ] }
        }
    },
    { "$match": { "isGrade1Greater": 1 } }
])