Bitwise operation and usage

Question

Consider this code:

x = 1        # 0001
x << 2       # Shift left 2 bits: 0100
# Result: 4

x | 2        # Bitwise OR: 0011
# Result: 3

x & 1              


        

Answer 1

There may be a better way to find where an array element is between two values, but as this example shows, the & works here, whereas and does not.

import numpy as np
a=np.array([1.2, 2.3, 3.4])
np.where((a>2) and (a<3))      
#Result: Value Error
np.where((a>2) & (a<3))
#Result: (array([1]),)