How to provide user name and password when connecting to a network share

Question

When connecting to a network share for which the current user (in my case, a network enabled service user) has no rights, name and password have to be provided.

I kn

Answer 1

I searched lots of methods and i did it my own way. You have to open a connection between two machine via command prompt NET USE command and after finishing your work clear the connection with command prompt NET USE "myconnection" /delete.

You must use Command Prompt process from code behind like this:

var savePath = @"\\servername\foldername\myfilename.jpg";
var filePath = @"C:\\temp\myfileTosave.jpg";

Usage is simple:

SaveACopyfileToServer(filePath, savePath);

Here is functions:

using System.IO
using System.Diagnostics;


public static void SaveACopyfileToServer(string filePath, string savePath)
    {
        var directory = Path.GetDirectoryName(savePath).Trim();
        var username = "loginusername";
        var password = "loginpassword";
        var filenameToSave = Path.GetFileName(savePath);

        if (!directory.EndsWith("\\"))
            filenameToSave = "\\" + filenameToSave;

        var command = "NET USE " + directory + " /delete";
        ExecuteCommand(command, 5000);

        command = "NET USE " + directory + " /user:" + username + " " + password;
        ExecuteCommand(command, 5000);

        command = " copy \"" + filePath + "\"  \"" + directory + filenameToSave + "\"";

        ExecuteCommand(command, 5000);


        command = "NET USE " + directory + " /delete";
        ExecuteCommand(command, 5000);
    }

And also ExecuteCommand function is:

public static int ExecuteCommand(string command, int timeout)
    {
        var processInfo = new ProcessStartInfo("cmd.exe", "/C " + command)
                              {
                                  CreateNoWindow = true, 
                                  UseShellExecute = false, 
                                  WorkingDirectory = "C:\\",
                              };

        var process = Process.Start(processInfo);
        process.WaitForExit(timeout);
        var exitCode = process.ExitCode;
        process.Close();
        return exitCode;
    } 

This functions worked very fast and stable for me.