I would do this with pandas, because I use pandas a lot
import pandas as pd
a = [1,2,3,3,3,4,5,6,6,7]
vc = pd.Series(a).value_counts()
vc[vc > 1].index.tolist()
Gives
[3,6]
Probably isn't very efficient, but it sure is less code than a lot of the other answers, so I thought I would contribute