Order of evaluation in C++ function parameters

Question

If we have three functions (foo, bar, and baz) that are composed like so...

foo(bar(), baz())

Is there any guarantee by the C++ standard th

Answer 1

C++17 specifies evaluation order for operators that was unspecified until C++17. See the question What are the evaluation order guarantees introduced by C++17? But note your expression

foo(bar(), baz())

has still unspecified evaluation order.