How to detect iPhone 5 (widescreen devices)?

Question

I\'ve just upgraded to XCode 4.5 GM and found out that you can now apply the \'4\" Retina\' size to your view controller in the storyboard.

Now if I want to create a

Answer 1

1. Add a 'New Swift File'-> AppDelegateEx.swift

2. add an extension to AppDelegate

   import UIKit
   extension AppDelegate {
        class func isIPhone5 () -> Bool{
            return max(UIScreen.mainScreen().bounds.width, UIScreen.mainScreen().bounds.height) == 568.0
       }
       class func isIPhone6 () -> Bool {
           return max(UIScreen.mainScreen().bounds.width, UIScreen.mainScreen().bounds.height) == 667.0
       }
       class func isIPhone6Plus () -> Bool {
           return max(UIScreen.mainScreen().bounds.width, UIScreen.mainScreen().bounds.height) == 736.0
       }  
   }
   

3. usage:

       if AppDelegate.isIPhone5() {
           collectionViewTopConstraint.constant = 2
       }else if AppDelegate.isIPhone6() {
           collectionViewTopConstraint.constant = 20
       }