In Python, how do I determine if an object is iterable?

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太阳男子
太阳男子 2020-11-22 00:35

Is there a method like isiterable? The only solution I have found so far is to call

hasattr(myObj, \'__iter__\')

But I am not

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  •  一向
    一向 (楼主)
    2020-11-22 01:05

    1. Checking for __iter__ works on sequence types, but it would fail on e.g. strings in Python 2. I would like to know the right answer too, until then, here is one possibility (which would work on strings, too):

      from __future__ import print_function
      
      try:
          some_object_iterator = iter(some_object)
      except TypeError as te:
          print(some_object, 'is not iterable')
      

      The iter built-in checks for the __iter__ method or in the case of strings the __getitem__ method.

    2. Another general pythonic approach is to assume an iterable, then fail gracefully if it does not work on the given object. The Python glossary:

      Pythonic programming style that determines an object's type by inspection of its method or attribute signature rather than by explicit relationship to some type object ("If it looks like a duck and quacks like a duck, it must be a duck.") By emphasizing interfaces rather than specific types, well-designed code improves its flexibility by allowing polymorphic substitution. Duck-typing avoids tests using type() or isinstance(). Instead, it typically employs the EAFP (Easier to Ask Forgiveness than Permission) style of programming.

      ...

      try:
         _ = (e for e in my_object)
      except TypeError:
         print my_object, 'is not iterable'
      
    3. The collections module provides some abstract base classes, which allow to ask classes or instances if they provide particular functionality, for example:

      from collections.abc import Iterable
      
      if isinstance(e, Iterable):
          # e is iterable
      

      However, this does not check for classes that are iterable through __getitem__.

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