Best way to display logs in pyqt?

Question

I am currently working on a GUI using qt designer. I am wondering how I should go about printing strings on the GUI that acts like a logger window. I am using pyqt5.

Answer 1

Here's a complete working example based on mfitzp's answer:

import sys
from PyQt4 import QtCore, QtGui
import logging

# Uncomment below for terminal log messages
# logging.basicConfig(level=logging.DEBUG, format=' %(asctime)s - %(name)s - %(levelname)s - %(message)s')    

class QPlainTextEditLogger(logging.Handler):
    def __init__(self, parent):
        super().__init__()
        self.widget = QtGui.QPlainTextEdit(parent)
        self.widget.setReadOnly(True)    

    def emit(self, record):
        msg = self.format(record)
        self.widget.appendPlainText(msg)    


class MyDialog(QtGui.QDialog, QPlainTextEditLogger):
    def __init__(self, parent=None):
        super().__init__(parent)    

        logTextBox = QPlainTextEditLogger(self)
        # You can format what is printed to text box
        logTextBox.setFormatter(logging.Formatter('%(asctime)s - %(levelname)s - %(message)s'))
        logging.getLogger().addHandler(logTextBox)
        # You can control the logging level
        logging.getLogger().setLevel(logging.DEBUG)

        self._button = QtGui.QPushButton(self)
        self._button.setText('Test Me')    

        layout = QtGui.QVBoxLayout()
        # Add the new logging box widget to the layout
        layout.addWidget(logTextBox.widget)
        layout.addWidget(self._button)
        self.setLayout(layout)    

        # Connect signal to slot
        self._button.clicked.connect(self.test)    

    def test(self):
        logging.debug('damn, a bug')
        logging.info('something to remember')
        logging.warning('that\'s not right')
        logging.error('foobar')

if (__name__ == '__main__'):
    app = None
    if (not QtGui.QApplication.instance()):
        app = QtGui.QApplication([])
    dlg = MyDialog()
    dlg.show()
    dlg.raise_()
    if (app):
        app.exec_()