What do these three dots in React do?

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不思量自难忘°
不思量自难忘° 2020-11-21 23:53

What does the ... do in this React (using JSX) code and what is it called?



        
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  •  伪装坚强ぢ
    2020-11-22 00:17

    Kudos to Brandon Morelli. He explained perfectly here, but links may die so I am just pasting the content below:

    The spread syntax is simply three dots: ... It allows an iterable to expand in places where 0+ arguments are expected. Definitions are tough without context. Let's explore some different use cases to help understand what this means.

    Example #1 — Inserting Arrays Take a look at the code below. In this code, we don’t use the spread syntax:

    var mid = [3, 4];
    var arr = [1, 2, mid, 5, 6];
    
    console.log(arr);

    Above, we’ve created an array named mid. We then create a second array which contains our mid array. Finally, we log out the result. What do you expect arr to print? Click run above to see what happens. Here is the output:

    [1, 2, [3, 4], 5, 6]
    

    Is that the result you expected? By inserting the mid array into the arr array, we’ve ended up with an array within an array. That’s fine if that was the goal. But what if you want only a single array with the values of 1 through 6? To accomplish this, we can use the spread syntax! Remember, the spread syntax allows the elements of our array to expand. Lets look at the code below. Everything is the same — except we’re now using the spread syntax to insert the mid array into the arr array:

    var mid = [3, 4];
    var arr = [1, 2, ...mid, 5, 6];
    
    console.log(arr);

    And when you hit the run button, here’s the result:

    [1, 2, 3, 4, 5, 6]
    

    Awesome! Remember the spread syntax definition you just read above? Here’s where it comes into play. As you can see, when we create the arr array and use the spread operator on the mid array, instead of just being inserted, the mid array expands. This expansion means that each and every element in the mid array is inserted into the arr array. Instead of nested arrays, the result is a single array of numbers ranging from 1 to 6.

    Example #2 — Math JavaScript has a built in math object that allows us to do some fun math calculations. In this example we’ll be looking at Math.max(). If you’re unfamiliar, Math.max() returns the largest of zero or more numbers. Here are a few examples:

    Math.max();
    // -Infinity
    Math.max(1, 2, 3);
    // 3
    Math.max(100, 3, 4);
    // 100
    

    As you can see, if you want to find the maximum value of multiple numbers, Math.max() requires multiple parameters. You unfortunately can’t simply use a single array as input. Before the spread syntax, the easiest way to use Math.max() on an array is to use .apply()

    var arr = [2, 4, 8, 6, 0];
    
    function max(arr) {
      return Math.max.apply(null, arr);
    }
    
    console.log(max(arr));

    It works, it’s just really annoying. Now take a look at how we do the same exact thing with the spread syntax:

    var arr = [2, 4, 8, 6, 0];
    var max = Math.max(...arr);
    
    console.log(max);

    Instead of having to create a function and utilize the apply method to return the result of Math.max() , we only need two lines of code! The spread syntax expands our array elements and inputs each element in our array individually into the Math.max() method!

    Example #3 — Copy an Array In JavaScript, you can’t just copy an array by setting a new variable equal to already existing array. Consider the following code example:

    var arr = ['a', 'b', 'c'];
    var arr2 = arr;
    
    console.log(arr2);

    When you press run, you’ll get the following output:

    ['a', 'b', 'c']
    

    Now, at first glance, it looks like it worked — it looks like we’ve copied the values of arr into arr2. But that’s not what has happened. You see, when working with objects in javascript (arrays are a type of object) we assign by reference, not by value. This means that arr2 has been assigned to the same reference as arr. In other words, anything we do to arr2 will also affect the original arr array (and vice versa). Take a look below:

    var arr = ['a', 'b', 'c'];
    var arr2 = arr;
    
    arr2.push('d');
    
    console.log(arr);

    Above, we’ve pushed a new element d into arr2. Yet, when we log out the value of arr, you’ll see that the d value was also added to that array:

    ['a', 'b', 'c', 'd']
    

    No need to fear though! We can use the spread operator! Consider the code below. It’s almost the same as above. Instead though, we’ve used the spread operator within a pair of square brackets:

    var arr = ['a', 'b', 'c'];
    var arr2 = [...arr];
    
    console.log(arr2);

    Hit run, and you’ll see the expected output:

    ['a', 'b', 'c']
    

    Above, the array values in arr expanded to become individual elements which were then assigned to arr2. We can now change the arr2 array as much as we’d like with no consequences on the original arr array:

    var arr = ['a', 'b', 'c'];
    var arr2 = [...arr];
    
    arr2.push('d');
    
    console.log(arr);

    Again, the reason this works is because the value of arr is expanded to fill the brackets of our arr2 array definition. Thus, we are setting arr2 to equal the individual values of arr instead of the reference to arr like we did in the first example.

    Bonus Example — String to Array As a fun final example, you can use the spread syntax to convert a string into an array. Simply use the spread syntax within a pair of square brackets:

    var str = "hello";
    var chars = [...str];
    
    console.log(chars);

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