equals vs Arrays.equals in Java

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走了就别回头了 2020-11-21 23:29

When comparing arrays in Java, are there any differences between the following 2 statements?

Object[] array1, array2;
array1.equals(array2);
Arrays.equals(ar         


        
8条回答
  •  旧巷少年郎
    2020-11-22 00:05

    Look inside the implementation of the two methods to understand them deeply:

    array1.equals(array2);
    
    /**
     * Indicates whether some other object is "equal to" this one.
     * 

    * The {@code equals} method implements an equivalence relation * on non-null object references: *

      *
    • It is reflexive: for any non-null reference value * {@code x}, {@code x.equals(x)} should return * {@code true}. *
    • It is symmetric: for any non-null reference values * {@code x} and {@code y}, {@code x.equals(y)} * should return {@code true} if and only if * {@code y.equals(x)} returns {@code true}. *
    • It is transitive: for any non-null reference values * {@code x}, {@code y}, and {@code z}, if * {@code x.equals(y)} returns {@code true} and * {@code y.equals(z)} returns {@code true}, then * {@code x.equals(z)} should return {@code true}. *
    • It is consistent: for any non-null reference values * {@code x} and {@code y}, multiple invocations of * {@code x.equals(y)} consistently return {@code true} * or consistently return {@code false}, provided no * information used in {@code equals} comparisons on the * objects is modified. *
    • For any non-null reference value {@code x}, * {@code x.equals(null)} should return {@code false}. *
    *

    * The {@code equals} method for class {@code Object} implements * the most discriminating possible equivalence relation on objects; * that is, for any non-null reference values {@code x} and * {@code y}, this method returns {@code true} if and only * if {@code x} and {@code y} refer to the same object * ({@code x == y} has the value {@code true}). *

    * Note that it is generally necessary to override the {@code hashCode} * method whenever this method is overridden, so as to maintain the * general contract for the {@code hashCode} method, which states * that equal objects must have equal hash codes. * * @param obj the reference object with which to compare. * @return {@code true} if this object is the same as the obj * argument; {@code false} otherwise. * @see #hashCode() * @see java.util.HashMap */ public boolean equals(Object obj) { return (this == obj); }

    while:

    Arrays.equals(array1, array2);
    
    /**
     * Returns true if the two specified arrays of Objects are
     * equal to one another.  The two arrays are considered equal if
     * both arrays contain the same number of elements, and all corresponding
     * pairs of elements in the two arrays are equal.  Two objects e1
     * and e2 are considered equal if (e1==null ? e2==null
     * : e1.equals(e2)).  In other words, the two arrays are equal if
     * they contain the same elements in the same order.  Also, two array
     * references are considered equal if both are null.

    * * @param a one array to be tested for equality * @param a2 the other array to be tested for equality * @return true if the two arrays are equal */ public static boolean equals(Object[] a, Object[] a2) { if (a==a2) return true; if (a==null || a2==null) return false; int length = a.length; if (a2.length != length) return false; for (int i=0; i

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