String count with overlapping occurrences

Question

What\'s the best way to count the number of occurrences of a given string, including overlap in Python? This is one way:

def function(string, str_to_search_f         


        

Answer 1

For a duplicated question i've decided to count it 3 by 3 and comparing the string e.g.

counted = 0

for i in range(len(string)):

    if string[i*3:(i+1)*3] == 'xox':
       counted = counted +1

print counted