Zipping streams using JDK8 with lambda (java.util.stream.Streams.zip)

Question

In JDK 8 with lambda b93 there was a class java.util.stream.Streams.zip in b93 which could be used to zip streams (this is illustrated in the tutorial Exploring Java8 Lambda

Answer 1

public class Tuple {
    private final S object1;
    private final T object2;

    public Tuple(S object1, T object2) {
        this.object1 = object1;
        this.object2 = object2;
    }

    public S getObject1() {
        return object1;
    }

    public T getObject2() {
        return object2;
    }
}


public class StreamUtils {

    private StreamUtils() {
    }

    public static  Stream> zipWithIndex(Stream stream) {
        Stream integerStream = IntStream.range(0, Integer.MAX_VALUE).boxed();
        Iterator integerIterator = integerStream.iterator();
        return stream.map(x -> new Tuple<>(integerIterator.next(), x));
    }
}