Why is floating point arithmetic in C# imprecise?

Question

Why does the following program print what it prints?

class Program
{
    static void Main(string[] args)
    {
        float f1 = 0.09f*100f;
        float f         


        

Answer 1

Floating point only has so many digits of precision. If you're seeing f1 == f2, it is because any difference requires more precision than a 32-bit float can represent.

I recommend reading What Every Computer Scientist Should Read About Floating Point