LINQ equivalent of foreach for IEnumerable

Question

I\'d like to do the equivalent of the following in LINQ, but I can\'t figure out how:

IEnumerable items = GetItems();
items.ForEach(i => i.DoS         


        

Answer 1

I respectually disagree with the notion that link extension methods should be side-effect free (not only because they aren't, any delegate can perform side effects).

Consider the following:

   public class Element {}

   public Enum ProcessType
   {
      This = 0, That = 1, SomethingElse = 2
   }

   public class Class1
   {
      private Dictionary> actions = 
         new Dictionary>();

      public Class1()
      {
         actions.Add( ProcessType.This, DoThis );
         actions.Add( ProcessType.That, DoThat );
         actions.Add( ProcessType.SomethingElse, DoSomethingElse );
      }

      // Element actions:

      // This example defines 3 distict actions
      // that can be applied to individual elements,
      // But for the sake of the argument, make
      // no assumption about how many distict
      // actions there may, and that there could
      // possibly be many more.

      public void DoThis( Element element )
      {
         // Do something to element
      }

      public void DoThat( Element element )
      {
         // Do something to element
      }

      public void DoSomethingElse( Element element )
      {
         // Do something to element
      }

      public void Apply( ProcessType processType, IEnumerable elements )
      {
         Action action = null;
         if( ! actions.TryGetValue( processType, out action ) )
            throw new ArgumentException("processType");
         foreach( element in elements ) 
            action(element);
      }
   }

What the example shows is really just a kind of late-binding that allows one invoke one of many possible actions having side-effects on a sequence of elements, without having to write a big switch construct to decode the value that defines the action and translate it into its corresponding method.