Why do this() and super() have to be the first statement in a constructor?

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北荒
北荒 2020-11-21 23:10

Java requires that if you call this() or super() in a constructor, it must be the first statement. Why?

For example:

public class MyClass {
    publi         


        
21条回答
  •  伪装坚强ぢ
    2020-11-21 23:32

    You asked why, and the other answers, imo, don't really say why it's ok to call your super's constructor, but only if it's the very first line. The reason is that you're not really calling the constructor. In C++, the equivalent syntax is

    MySubClass: MyClass {
    
    public:
    
     MySubClass(int a, int b): MyClass(a+b)
     {
     }
    
    };
    

    When you see the initializer clause on its own like that, before the open brace, you know it's special. It runs before any of the rest of the constructor runs and in fact before any of the member variables are initialized. It's not that different for Java. There's a way to get some code (other constructors) to run before the constructor really starts, before any members of the subclass are initialized. And that way is to put the "call" (eg super) on the very first line. (In a way, that super or this is kind of before the first open brace, even though you type it after, because it will be executed before you get to the point that everything is fully constructed.) Any other code after the open brace (like int c = a + b;) makes the compiler say "oh, ok, no other constructors, we can initialize everything then." So it runs off and initializes your super class and your members and whatnot and then starts executing the code after the open brace.

    If, a few lines later, it meets some code saying "oh yeah when you're constructing this object, here are the parameters I want you to pass along to the constructor for the base class", it's too late and it doesn't make any sense. So you get a compiler error.

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