I want to have 2 models in one view. The page contains both LoginViewModel
and RegisterViewModel
.
e.g.
pub
I'd recommend using Html.RenderAction
and PartialViewResults to accomplish this; it will allow you to display the same data, but each partial view would still have a single view model and removes the need for a BigViewModel
So your view contain something like the following:
@Html.RenderAction("Login")
@Html.RenderAction("Register")
Where Login
& Register
are both actions in your controller defined like the following:
public PartialViewResult Login( )
{
return PartialView( "Login", new LoginViewModel() );
}
public PartialViewResult Register( )
{
return PartialView( "Register", new RegisterViewModel() );
}
The Login
& Register
would then be user controls residing in either the current View folder, or in the Shared folder and would like something like this:
/Views/Shared/Login.cshtml: (or /Views/MyView/Login.cshtml)
@model LoginViewModel
@using (Html.BeginForm("Login", "Auth", FormMethod.Post))
{
@Html.TextBoxFor(model => model.Email)
@Html.PasswordFor(model => model.Password)
}
/Views/Shared/Register.cshtml: (or /Views/MyView/Register.cshtml)
@model ViewModel.RegisterViewModel
@using (Html.BeginForm("Login", "Auth", FormMethod.Post))
{
@Html.TextBoxFor(model => model.Name)
@Html.TextBoxFor(model => model.Email)
@Html.PasswordFor(model => model.Password)
}
And there you have a single controller action, view and view file for each action with each totally distinct and not reliant upon one another for anything.