How to resize an Image C#

Question

As Size, Width and Height are Get() properties of System.Drawing.Image;
How can I resize an Image object

Answer 1

This is the code that I worked out for a specific requirement ie: the destination is always in landscape ratio. It should give you a good start.

public Image ResizeImage(Image source, RectangleF destinationBounds)
{
    RectangleF sourceBounds = new RectangleF(0.0f,0.0f,(float)source.Width, (float)source.Height);
    RectangleF scaleBounds = new RectangleF();

    Image destinationImage = new Bitmap((int)destinationBounds.Width, (int)destinationBounds.Height);
    Graphics graph = Graphics.FromImage(destinationImage);
    graph.InterpolationMode =
        System.Drawing.Drawing2D.InterpolationMode.HighQualityBicubic;

    // Fill with background color
    graph.FillRectangle(new SolidBrush(System.Drawing.Color.White), destinationBounds);

    float resizeRatio, sourceRatio;
    float scaleWidth, scaleHeight;

    sourceRatio = (float)source.Width / (float)source.Height;

    if (sourceRatio >= 1.0f)
    {
        //landscape
        resizeRatio = destinationBounds.Width / sourceBounds.Width;
        scaleWidth = destinationBounds.Width;
        scaleHeight = sourceBounds.Height * resizeRatio;
        float trimValue = destinationBounds.Height - scaleHeight;
        graph.DrawImage(source, 0, (trimValue / 2), destinationBounds.Width, scaleHeight);
    }
    else
    {
        //portrait
        resizeRatio = destinationBounds.Height/sourceBounds.Height;
        scaleWidth = sourceBounds.Width * resizeRatio;
        scaleHeight = destinationBounds.Height;
        float trimValue = destinationBounds.Width - scaleWidth;
        graph.DrawImage(source, (trimValue / 2), 0, scaleWidth, destinationBounds.Height);
    }

    return destinationImage;

}