Renaming files by reformatting existing filenames - placeholders in replacement strings used with the -replace operator

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醉话见心
醉话见心 2020-11-21 22:23

I have a few video file like this: VideoName_s01e01.mp4 where the season and episodes are variables. I want to add an underscore (\"_\") between the s??

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  •  醉话见心
    2020-11-21 23:01

    Martin Brandl's answer provides an elegant and effective solution, but it's worth digging deeper:

    PowerShell's -replace operator (... -replace [, ]):

    • Takes a regular expression as its first operand, (the search expression), and invariably matches globally, i.e., it replaces all matches.

      • 'bar' -replace '[ra]', '@' -> 'b@@'
    • Specifying a replacement expression, , is optional, in which case the empty string is substituted for what matched, resulting in its effective removal.

      • 'bar' -replace '[ra]' -> 'b'
    • If is specified, it supports two forms:

      • v6.1+ (PowerShell Core only): A script block ({ ... }) as the replacement operand, which offers fully dynamic calculation of the replacement string on a per-match basis - see this answer for an example.

        • 'bar' -replace '[ra]', { '{' + $_.Value + '}' } -> 'b{a}{r}'
      • A string containing an expression that can reference what the regular expression captured (and didn't capture), explained below.

        • 'bar' -replace '[ra]', '{$&}' -> 'b{a}{r}'
    • -replace matches case-insensitively (and can also be written as -ireplace); to perform case-sensitive matching, use the form -creplace.


    The "replacement language" for referencing regex captures in a string-typed operand is itself not a regular expression - no matching happens there, only references to the results of the regex matching are supported.

    Notably,

    • PowerShell does not explain the syntax of replacement strings in its Get-Help about_comparison_operators help topic,

    • but the information can be found in the Substitutions in Regular Expressions .NET framework help topic, because PowerShell's -replace uses the Regex.Replace() method behind the scenes.

    For convenience, here are the references supported in the string (excerpted from the page linked above, with emphasis and annotations added):

    • $number (e.g., $1) ... Includes the last substring matched by the capture group that is identified by the 1-based number, where number is a decimal value, in the replacement string.

      • Annotations:
        • Including (...), a parenthesized subexpression, in the regex implicitly creates a capture group (capturing group). By default, such capture groups are unnamed and must be referenced by their 1-based (decimal) index reflecting the order in which they appear in the regex, so that $1 refers to what the 1st group in your regex captured, $2 to what the 2nd captured, ...

        • The form ${number} (e.g., ${1}) for disambiguation of the number is also supported (e.g., to make sure that $1 is recognized even if followed by, say, 000, use ${1}000).

        • Instead of relying on indices to refer to unnamed capture groups, you can name capture groups and refer to them by name - see next point.

        • If you're not interested in what the capture group matched, you can opt to ignore it by turning it into a non-capturing group with (?:...).

    • ${name} ... Includes the last substring matched by the named group that is designated by (?<name>...) in the replacement string.

    • $$ ... Includes a single "$" literal in the replacement string.

    • $& ... Includes a copy of the entire match in the replacement string ($0 works too, even though it isn't directly documented).

    • $` ... Includes all the text of the input string before the match in the replacement string.

    • $' ... Includes all the text of the input string after the match in the replacement string.

    • $+ ... Includes the last group captured in the replacement string. [This relieves you of the need to know the last group's specific index.]

    • $_ ... Includes the entire input string in the replacement string.

    Finally, note that:

    • -replace invariably matches globally, so if the input string contains multiple matches, the replacements above apply to each match.

    • It is generally preferable to use '...' (single quotes) for both the regex and the replacement string, because single-quoted strings are non-expanding (non-interpolating), and therefore avoid confusion with PowerShell's own up-front expansions of $-prefixed tokens and interpretation of ` chars.
      If you do need to include a PowerShell variable, you have three options:

    • Use "..." (expanding strings) and `-escape $ instances that are meant for the regex engine; e.g., `$1 in the following example:
      'abc' -replace '(a)', "[`$1]-$HOME-", which yields something like [a]-C:\Users\jdoe-bc

    • Build your string from literal pieces and variable references using string concatenation (+); e.g.:
      'abc' -replace '(a)', ('[$1]-' + $HOME + '-')

    • Use -f, the string-formatting operator string concatenation; e.g.:
      'abc' -replace '(a)', ('[$1]-{0}-' -f $HOME)

    • Given that you need to use $$ to escape a literal $ in the replacement string, use the following idiom to use a variable whose value you want to use literally:

      • ... -replace , $var.Replace('$', '$$')
      • This relies on the [string]::Replace() method performing literal substring replacements.
        On a side note, this method is an alternative to -replace in simple cases, but note that it is case-sensitive by default.
      • Alternatively, use a nested -replace call, but the syntax is tricky due to the escaping requirements:
        ... -replace , ($var -replace '\$', '$$$$')

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