Deserialize json object into dynamic object using Json.net

Question

Is it possible to return a dynamic object from a json deserialization using json.net? I would like to do something like this:

dynamic jsonResponse = JsonConv         


        

Answer 1

If you use JSON.NET with old version which didn't JObject.

This is another simple way to make a dynamic object from JSON: https://github.com/chsword/jdynamic

NuGet Install

PM> Install-Package JDynamic

Support using string index to access member like:

dynamic json = new JDynamic("{a:{a:1}}");
Assert.AreEqual(1, json["a"]["a"]);

Test Case

And you can use this util as following :

Get the value directly

dynamic json = new JDynamic("1");

//json.Value

2.Get the member in the json object

dynamic json = new JDynamic("{a:'abc'}");
//json.a is a string "abc"

dynamic json = new JDynamic("{a:3.1416}");
//json.a is 3.1416m

dynamic json = new JDynamic("{a:1}");
//json.a is integer: 1

3.IEnumerable

dynamic json = new JDynamic("[1,2,3]");
/json.Length/json.Count is 3
//And you can use json[0]/ json[2] to get the elements

dynamic json = new JDynamic("{a:[1,2,3]}");
//json.a.Length /json.a.Count is 3.
//And you can use  json.a[0]/ json.a[2] to get the elements

dynamic json = new JDynamic("[{b:1},{c:1}]");
//json.Length/json.Count is 2.
//And you can use the  json[0].b/json[1].c to get the num.

Other

dynamic json = new JDynamic("{a:{a:1} }");

//json.a.a is 1.