Determine whether an array contains a value [duplicate]

Answer 1

Array.prototype.includes()

In ES2016, there is Array.prototype.includes().

The includes() method determines whether an array includes a certain element, returning true or false as appropriate.

Example

["Sam", "Great", "Sample", "High"].includes("Sam"); // true

Support

According to kangax and MDN, the following platforms are supported:

• Chrome 47
• Edge 14
• Firefox 43
• Opera 34
• Safari 9
• Node 6

Support can be expanded using Babel (using babel-polyfill) or core-js. MDN also provides a polyfill:

if (![].includes) {
  Array.prototype.includes = function(searchElement /*, fromIndex*/ ) {
    'use strict';
    var O = Object(this);
    var len = parseInt(O.length) || 0;
    if (len === 0) {
      return false;
    }
    var n = parseInt(arguments[1]) || 0;
    var k;
    if (n >= 0) {
      k = n;
    } else {
      k = len + n;
      if (k < 0) {k = 0;}
    }
    var currentElement;
    while (k < len) {
      currentElement = O[k];
      if (searchElement === currentElement ||
         (searchElement !== searchElement && currentElement !== currentElement)) {
        return true;
      }
      k++;
    }
    return false;
  };
}