Split data.frame based on levels of a factor into new data.frames

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一个人的身影
一个人的身影 2020-11-21 16:44

I\'m trying to create separate data.frame objects based on levels of a factor. So if I have:

df <- data.frame(
  x=rnorm(25),
  y=rnorm(25),
         


        
2条回答
  •  北恋
    北恋 (楼主)
    2020-11-21 17:31

    I think that split does exactly what you want.

    Notice that X is a list of data frames, as seen by str:

    X <- split(df, df$g)
    str(X)
    

    If you want individual object with the group g names you could assign the elements of X from split to objects of those names, though this seems like extra work when you can just index the data frames from the list split creates.

    #I used lapply just to drop the third column g which is no longer needed.
    Y <- lapply(seq_along(X), function(x) as.data.frame(X[[x]])[, 1:2]) 
    
    #Assign the dataframes in the list Y to individual objects
    A <- Y[[1]]
    B <- Y[[2]]
    C <- Y[[3]]
    D <- Y[[4]]
    E <- Y[[5]]
    
    #Or use lapply with assign to assign each piece to an object all at once
    lapply(seq_along(Y), function(x) {
        assign(c("A", "B", "C", "D", "E")[x], Y[[x]], envir=.GlobalEnv)
        }
    )
    

    Edit Or even better than using lapply to assign to the global environment use list2env:

    names(Y) <- c("A", "B", "C", "D", "E")
    list2env(Y, envir = .GlobalEnv)
    A
    

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