uint8_t can't be printed with cout

Question

I have a weird problem about working with integers in C++.

I wrote a simple program that sets a value to a variable and then prints it, but it is not working as expe

Answer 1

Adding a unary + operator before the variable of any primitive data type will give printable numerical value instead of ASCII character(in case of char type).

uint8_t aa = 5;
cout<<"value is "<< +aa <