if/else in a list comprehension

Question

How can I do the following in Python?

row = [unicode(x.strip()) for x in row if x is not None else \'\']

Essentially:

1. replace

Answer 1

Here is another illustrative example:

>>> print(", ".join(["ha" if i else "Ha" for i in range(3)]) + "!")
Ha, ha, ha!

It exploits the fact that if i evaluates to False for 0 and to True for all other values generated by the function range(). Therefore the list comprehension evaluates as follows:

>>> ["ha" if i else "Ha" for i in range(3)]
['Ha', 'ha', 'ha']