OK, there are few ways to do that, but let's start with the simplest one and latest approach to do this, this function is called find()
.
Just be careful when you using find
to as even IE11 dosn't support it, so it needs to be transpiled...
so you have this object as you said:
var jsObjects = [
{a: 1, b: 2},
{a: 3, b: 4},
{a: 5, b: 6},
{a: 7, b: 8}
];
and you can write a function and get it like this:
function filterValue(obj, key, value) {
return obj.find(function(v){ return v[key] === value});
}
and use the function like this:
filterValue(jsObjects, "b", 6); //{a: 5, b: 6}
Also in ES6 for even shortened version:
const filterValue = (obj, key, value)=> obj.find(v => v[key] === value);
This method only return the first value which match..., for better result and browser support, you can use filter
:
const filterValue = (obj, key, value)=> obj.filter(v => v[key] === value);
and we will return [{a: 5, b: 6}]
...
This method will return an array instead...
You simpley use for loop as well, create a function like this:
function filteredArray(arr, key, value) {
const newArray = [];
for(i=0, l=arr.length; i
and call it like this:
filteredArray(jsObjects, "b", 6); //[{a: 5, b: 6}]