How to parse a string to an int in C++?

Question

What\'s the C++ way of parsing a string (given as char *) into an int? Robust and clear error handling is a plus (instead of returning zero).

Answer 1

This is a safer C way than atoi()

const char* str = "123";
int i;

if(sscanf(str, "%d", &i)  == EOF )
{
   /* error */
}

C++ with standard library stringstream: (thanks CMS )

int str2int (const string &str) {
  stringstream ss(str);
  int num;
  if((ss >> num).fail())
  { 
      //ERROR 
  }
  return num;
}

With boost library: (thanks jk)

#include 
#include 

try
{
    std::string str = "123";
    int number = boost::lexical_cast< int >( str );
}
catch( const boost::bad_lexical_cast & )
{
    // Error
}

Edit: Fixed the stringstream version so that it handles errors. (thanks to CMS's and jk's comment on original post)