this on a C++ compiler
The C++ compiler will silently lookup for a symbol if it does not find it immediately. Sometimes, most of the time, it is good:
- using the mother class' method if you did not overloaded it in the child class.
- promoting a value of a type into another type
But sometimes, You just don't want the compiler to guess. You want the compiler to pick-up the right symbol and not another.
For me, those times are when, within a method, I want to access to a member method or member variable. I just don't want some random symbol picked up just because I wrote printf instead of print. this->printf would not have compiled.
The point is that, with C legacy libraries (§), legacy code written years ago (§§), or whatever could happen in a language where copy/pasting is an obsolete but still active feature, sometimes, telling the compiler to not play wits is a great idea.
These are the reasons I use this.
(§) it's still a kind of mystery to me, but I now wonder if the fact you include the header in your source, is the reason all the legacy C libraries symbols will pollute your global namespace
(§§) realizing that "you need to include a header, but that including this header will break your code because it uses some dumb macro with a generic name" is one of those russian roulette moments of a coder's life
