What is the error “Every derived table must have its own alias” in MySQL?

Question

I am running this query on MySQL

SELECT ID FROM (
    SELECT ID, msisdn
    FROM (
        SELECT * FROM TT2
    )
);

and it is giving this

Answer 1

I think it's asking you to do this:

SELECT ID
FROM (SELECT ID,
             msisdn 
      FROM (SELECT * FROM TT2) as myalias
     ) as anotheralias;

But why would you write this query in the first place?